The 4 equations of accelerated motion (UVAST)

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A student drops a stone off a high cliff by the ocean. After 3.5 seconds he sees the splash caused by the stone he threw.

a) What is the height of the cliff?

b) What is the speed with which the stone hit the water?

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Answer:
a) We use: $latex s = ut + \frac{1}{2}at^{2}$ u = 0 m/s. t = 3.5 s. a = g. Therefore s = 60 m.

b) We use v = u + at = 34.3 m/s.

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Uniformly accelerated motion 2