I show you how angular speed, given by “omega” can be used

**When you're done with the video,** answer a related question.

Show me the question
A large clock, with a minute hand of 5 meters, is malfunctioning, counting 0.9 seconds every 1 second.

a) What is the angular speed of the minute hand?

b) What is the angular displacement of the minute hand from the moment the clock shows 12:00 pm until the moment it shows 1:30 pm?

c) What is the linear speed of the tip of the minute hand?

Show answer

Answer:
a) Because the clock is malfunctioning, the minute hand makes one full cycle in $latex \frac{3600}{0.9}=4000$ seconds.The formula for the angular speed is simply $latex \omega = \frac{angular displacement}{time} = \frac{2\pi}{4000} = 0.00157$ rad/s.

b) In this case, the malfunctioning of the clock does not matter. The minute hand will go round 1 time and a half which means a displacement of 3π radians.

c) The formula for linear speed is v= ωr. In our case, r = 5m, therefore v = 0.00785 m/s = 7.85 mm/s.

Next up:
Centripetal acceleration and force